Defending champions Mumbai Indians, who returned to the rhythm with two consecutive wins, will be a strong contenders for victory against the last-placed Sunrisers Hyderabad in the Indian Premier League match here on Tuesday. Mumbai defeated in-form Chennai Super Kings by four wickets in their last match, thanks to a stormy innings by Keiron Pollard.
On the other hand, the Sunrisers suffered a humiliating 55-run defeat against the Rajasthan Royals, the team’s sixth loss in seven matches in the current season. The team is going through a transition, with captain
Mumbai openers Rohit Sharma (250 runs) and Quinton Dickock (155 runs) would like to once again give a good start to the five-time champion team and turn a good start into big innings.
Mumbai’s aggressive middle order has been successful in the last two matches, which is a relief for the team management. Pollard (168 runs), who played an unbeaten 87-ball 87-run match-winning innings against Chennai, will look to maintain this form.
Krunal Pandya (100 runs), Hardik Pandya (52 runs) and Suryakumar Yadav (173 runs) are capable of demolishing the opposing team and will try to perform in unison.
It will also have to be seen whether the Mumbai team gives a chance to one of Ishan Kishan and Jayant Yadav in place of James Neesham. Neesham has neither played a big innings nor got a wicket.
Mumbai’s bowlers, however, will have to forget the poor performance against Chennai Super Kings and start afresh.
Jaspreet Bumrah (six wickets) and Trent Boult (eight wickets) have bowled brilliantly in the death overs and have been able to trouble the Sunrisers batsmen.
Leg-spinner Rahul Chahar (11 wickets) is Mumbai’s most successful bowler but needs support from Krunal who has managed to take just three wickets.
Pollard also took two important wickets in the last match and can play the role of fifth or sixth bowler.
Sunrisers are not taking the name of the problems being reduced. The team is heavily reliant on its top order, especially Johnny Bairstow (248 runs) but the middle order has disappointed the team on most occasions.
Against the Royals, the team opened the innings with Manish Pandey and Bairstow, while Williamson came in at number three. If the team maintains the same order, then all three will have to score big on most occasions.
Vijay Shankar (58 runs), Kedar Jadhav (40 runs), Abdul Samad (36 runs) and Mohammad Nabi (31 runs) will also have to contribute better with the bat.
Star leg-spinner Rashid Khan is the team’s most successful bowler with 10 wickets but fast bowlers Bhuvneshwar Kumar (three wickets) and Khalil Ahmed (four wickets) have not lived up to expectations.
It has to be seen whether Sandeep Sharma gets a second chance or is fed to Siddharth Kaul.
The teams are as follows:
Mumbai Indians: Rohit Sharma (Captain), Adam Milne, Aditya Tare, Anmolpreet Singh, Anukul Roy, Arjun Tendulkar, Chris Lynn, Dhawal Kulkarni, Hardik Pandya, Ishan Kishan, James Neesham, Jaspreet Bumrah, Jayant Yadav, Kairan Pollard, Krunal Pandya , Marco Jenson, Mohsin Khan, Nathan Coulter Nile, Piyush Chawla, Quinton Dickock, Rahul Chahar, Saurabh Tiwari, Suryakumar Yadav, Trent Boult and Yudhveer Singh.
Sunrisers Hyderabad: Kane Williamson (Captain), David Warner, Johnny Bairstow, Manish Pandey, Srivats Goswami, Wriddhiman Saha, Priyam Garg, Vijay Shankar, Abhishek Sharma, Abdul Samad, Virat Singh, Jason Holder, Mohammad Nabi, Rashid Khan, Shahbaz Nadeem , Bhuvaneshwar Kumar, Sandeep Sharma, Khalil Ahmed, Siddharth Kaul, Basil Thampi, Jagdish Suchit, Kedar Jadhav and Mujib ur Rehman.